Question:
The Vividh Bharati station of All India Radio, Kozhikode, broadcasts on a frequency of \( 1500\,\text{kHz} \). What is the wavelength of the electromagnetic radiation emitted by the transmitter? \( (c = 3\times10^8\,\text{m s}^{-1}) \)
The Vividh Bharati station of All India Radio, Kozhikode, broadcasts on a frequency of \( 1500\,\text{kHz} \). What is the wavelength of the electromagnetic radiation emitted by the transmitter? \( (c = 3\times10^8\,\text{m s}^{-1}) \)
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Always convert kHz to Hz before using formula.
Updated On: Apr 21, 2026
- \(200\,\text{m} \)
- \(300\,\text{m} \)
- \(100\,\text{m} \)
- \(250\,\text{m} \)
- \(150\,\text{m} \)
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The Correct Option is A
Solution and Explanation
Concept:
\[
\lambda = \frac{c}{f}
\]
Step 1: Convert frequency.
\[ f = 1500 \times 10^3 \]
Step 2: Calculate.
\[ \lambda = \frac{3\times10^8}{1.5\times10^6} = 200\,\text{m} \]
Step 1: Convert frequency.
\[ f = 1500 \times 10^3 \]
Step 2: Calculate.
\[ \lambda = \frac{3\times10^8}{1.5\times10^6} = 200\,\text{m} \]
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