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the vector sum of two forces vec a and vec b is pe
Question:
The vector sum of two forces $\vec{A}$ and $\vec{B}$ is perpendicular to their vector difference. Hence forces $\vec{A}$ and $\vec{B}$ are}
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Sum and Difference vectors are perpendicular only for equal magnitude vectors (diagonals of a rhombus).
MHT CET - 2025
MHT CET
Updated On:
Jun 19, 2026
perpendicular to each other.
parallel to each other.
unequal in magnitude.
equal in magnitude.
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The Correct Option is
D
Solution and Explanation
Step 1: Concept
If two vectors are perpendicular, their dot product is zero.
Step 2: Analysis
$(\vec{A} + \vec{B}) \cdot (\vec{A} - \vec{B}) = 0$.
Step 3: Calculation
$\vec{A} \cdot \vec{A} - \vec{A} \cdot \vec{B} + \vec{B} \cdot \vec{A} - \vec{B} \cdot \vec{B} = 0$
$A^2 - B^2 = 0 \implies A^2 = B^2 \implies |\vec{A}| = |\vec{B}|$.
Step 4: Conclusion
Hence, the forces are equal in magnitude.
Final Answer:
(D)
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