Step 1: Understanding the Question:
The question asks for the vector equation of a line passing through two specified coordinate points, P and Q, in three-dimensional space.
Step 2: Key Formula or Approach:
The vector equation of a straight line passing through a point with position vector $\vec{a}$ and moving along a direction vector $\vec{m}$ is written as:
$$\vec{r} = \vec{a} + \lambda \vec{m}$$
When the line passes through two points $\text{P}(\vec{a})$ and $\text{Q}(\vec{b})$, the direction vector is simply the difference vector between them:
$$\vec{m} = \vec{b} - \vec{a}$$
Step 3: Detailed Explanation:
1. Identify the position vector of the first passing point $\text{P}(1, 2, 3)$, which serves as our base vector $\vec{a}$:
$$\vec{a} = 1\hat{i} + 2\hat{j} + 3\hat{k} = \hat{i} + 2\hat{j} + 3\hat{k}$$
2. Identify the position vector of the second point $\text{Q}(2, 3, 4)$, denoted as $\vec{b}$:
$$\vec{b} = 2\hat{i} + 3\hat{j} + 4\hat{k}$$
3. Compute the direction vector $\vec{m}$ by taking the difference $\vec{b} - \vec{a}$:
$$\vec{m} = (2 - 1)\hat{i} + (3 - 2)\hat{j} + (4 - 3)\hat{k}$$
$$\vec{m} = 1\hat{i} + 1\hat{j} + 1\hat{k} = \hat{i} + \hat{j} + \hat{k}$$
4. Substitute $\vec{a}$ and $\vec{m}$ into the standard line formulation:
$$\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} + \hat{j} + \hat{k})$$
Step 4: Final Answer:
The correct vector equation is $(\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} + \hat{j} + \hat{k})$, which matches option (A).