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the value of vec a times vec b 2 vec a cdot vec b
Question:
The value of \(\{(\vec{a} \times \vec{b})^2 + (\vec{a}\cdot \vec{b})^2\\div a^2 b^2\) is}
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Always remember: \(|\vec{a}\times\vec{b}|^2 + (\vec{a}\cdot\vec{b})^2 = a^2 b^2\).
MET - 2021
MET
Updated On:
Apr 15, 2026
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1
2
None of these
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The Correct Option is
B
Solution and Explanation
Concept:
Vector identity: \(|\vec{a}\times\vec{b}|^2 + (\vec{a}\cdot\vec{b})^2 = a^2 b^2\).
Step 1:
Substitute. \[ \frac{a^2 b^2}{a^2 b^2} = 1 \]
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