Step 1: Right-hand limit
For \(x\) slightly above \(3\), \([x]=3\), so the fraction is \(\frac{0}{x-3}=0\). The limit is \(0\).
Step 2: Left-hand limit
For \(x\) slightly below \(3\), \([x]=2\), so the fraction is \(\frac{-1}{x-3}\). As \(x\to3^-\), \(x-3\to0^-\), and the fraction tends to \(+\infty\).
Step 3: Compare
The two sided limits differ (\(0\) and \(+\infty\)), so the limit does not exist. Option (D).
Final Answer:
The limit does not exist, option (D).
\[ \boxed{\text{(D)}} \]