We know that 32 = 2 × 2 × 2 × 2 × 2 = 25
Therefore, log2 32 = log2 (25) = 5
Conclusion:
The value of log2 32 is (3) 5.
Consider two distinct positive numbers \( m, n \) with \( m > n \). Let \[ x = n^{\log_n m}, \quad y = m^{\log_m n}. \] The relation between \( x \) and \( y \) is -
If \[ \log_{p^{1/2}} y \times \log_{y^{1/2}} p = 16, \] then find the value of the given expression.