Correct answer: ±3
Explanation:
Given: \(\log_{3} x^2 = 2\)
Using logarithmic identity: \(\log_b a = c \Rightarrow a = b^c\)
So, \(x^2 = 3^2 = 9\)
Taking square root on both sides: \(x = \pm 3\)
So, x = ±3. Since ±3 is not listed directly, among the options, only 3 and -3 are valid.
Consider two distinct positive numbers \( m, n \) with \( m > n \). Let \[ x = n^{\log_n m}, \quad y = m^{\log_m n}. \] The relation between \( x \) and \( y \) is -
If \[ \log_{p^{1/2}} y \times \log_{y^{1/2}} p = 16, \] then find the value of the given expression.