Question:

The value of limₓtₒᵢₙfty(fraca₁¹/x+a₂¹/x+⋯+aₙ¹/xn)ⁿx, aᵢ>0 is

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Limits of the form (1+(k)/(x))ˣ tend to exponentials.
Updated On: Mar 19, 2026
  • a₁+a₂+⋯+aₙ
  • eᵃ_¹⁺ᵃ_²⁺⋯⁺ᵃ_ⁿ
  • (a₁+a₂+⋯+aₙ)/(n)
  • a₁a₂⋯ aₙ
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The Correct Option is D

Solution and Explanation

For large x: aᵢ¹/x≈ 1+(ln aᵢ)/(x) Hence, (1+(sum ln aᵢ)/(nx))ⁿx → eˢᵘᵐ lⁿ ᵃ_ⁱ = a₁a₂⋯ aₙ
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