Question:

The value of
\[ \lim_{x \to \infty} \left(a_1^{1/x} + a_2^{1/x} + \cdots + a_n^{1/x}\right)^{n x}, \quad a_i > 0 \]

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Use logarithms to evaluate limits of powers.
Updated On: Mar 23, 2026
  • \(a_1+a_2+\cdots+a_n\)
  • \(e^{a_1+a_2+\cdots+a_n}\)
  • \(\dfrac{a_1+a_2+\cdots+a_n}{n}\)
  • a₁a₂⋯ aₙ
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The Correct Option is D

Solution and Explanation

As \(x \to \infty\),
\[ a_i^{1/x} \approx 1 + \frac{\ln a_i}{x}. \]
Taking logarithm and limit gives:
\[ \ln L = \sum_{i=1}^{n} \ln a_i \implies L = a_1 a_2 \cdots a_n. \]
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