Question:

The value of limₙtₒᵢₙfty(1+2+3+⋯+n)/(n²+100) is equal to:

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Compare highest powers of n in limits at infinity.
Updated On: Mar 20, 2026
  • \(\infty\)
  • \(\dfrac{1}{2}\)
  • \(2\)
  • 0
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The Correct Option is B

Solution and Explanation


Step 1:
1+2+⋯+n=(n(n+1))/(2)
Step 2:
((n(n+1))/(2))/(n²+100) =(n²+n)/(2n²+200)
Step 3:
Divide by n²: limₙtₒᵢₙfty(1+(1)/(n))/(2+(200)/(n²))=(1)/(2)
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