Concept:
To simplify nested radicals of the form \( \sqrt{a \pm 2\sqrt{b}} \), we try to express the term inside the square root as a perfect square \( (x \pm y)^2 = x^2 + y^2 \pm 2xy \).
Step 1: Simplifying the nested radicals.
For \( 4 + 2\sqrt{3} \), we need two numbers whose sum is 4 and product is 3. These are 3 and 1.
\[
4 + 2\sqrt{3} = 3 + 1 + 2\sqrt{3}= (\sqrt{3})^2 + (1)^2 + 2(\sqrt{3})(1) = (\sqrt{3} + 1)^2
\]
Similarly:
\[
4 - 2\sqrt{3} = (\sqrt{3} - 1)^2
\]
Step 2: Calculating the final value.
\[
\sqrt{(\sqrt{3} + 1)^2} - \sqrt{(\sqrt{3} - 1)^2} = (\sqrt{3} + 1) - (\sqrt{3} - 1)
\]
\[
= \sqrt{3} + 1 - \sqrt{3} + 1 = 2
\]