Question:

The value of $\int_{1}^{e}\frac{1}{x}dx$ is equal to

Show Hint

Integration Tip: Remember that in calculus contexts, $\log(x)$ overwhelmingly refers to the natural logarithm $\ln(x)$ with base $e$.
Updated On: Apr 30, 2026
  • e
  • 1
  • $e^{2}$
  • $e^{2}-e$
  • 0
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Concept:
The integral of $\frac{1}{x}$ with respect to $x$ is one of the foundational calculus formulas: $\int \frac{1}{x} dx = \log|x| + C$ (using the natural logarithm). Once the antiderivative is found, use the Fundamental Theorem of Calculus to evaluate the bounds.

Step 1: Find the antiderivative.

Integrate the function $\frac{1}{x}$: $$\int \frac{1}{x} dx = \log|x|$$

Step 2: Set up the evaluation limits.

Apply the limits of integration from $1$ to $e$: $$[\log|x|]_{1}^{e}$$

Step 3: Substitute the upper limit.

Plug the upper limit $e$ into the antiderivative: $$\log|e| = 1$$ *(Note: The natural logarithm of Euler's number $e$ is exactly 1).*

Step 4: Substitute the lower limit.

Plug the lower limit $1$ into the antiderivative: $$\log|1| = 0$$

Step 5: Subtract to find the final value.

Subtract the lower limit evaluation from the upper limit evaluation: $$1 - 0 = 1$$ Hence the correct answer is (B) 1.
Was this answer helpful?
2
0