Question:

The value of $\displaystyle \int_{0}^{1} x(1-x)^4 \, dx$ is equal to:

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Expand polynomial first for easy definite integration.
Updated On: Apr 24, 2026
  • $\frac{1}{60}$
  • $\frac{1}{15}$
  • $\frac{1}{30}$
  • $\frac{1}{45}$
  • $\frac{1}{20}$
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The Correct Option is C

Solution and Explanation

Concept:
• Expand and integrate term-wise

Step 1:
Expand $(1-x)^4$
\[ (1-x)^4 = 1 - 4x + 6x^2 - 4x^3 + x^4 \]

Step 2:
Multiply by $x$
\[ x(1-x)^4 = x - 4x^2 + 6x^3 - 4x^4 + x^5 \]

Step 3:
Integrate term-wise
\[ \int_{0}^{1} x\,dx = \frac{1}{2} \] \[ \int_{0}^{1} x^2 dx = \frac{1}{3}, \quad \int x^3 dx = \frac{1}{4} \] \[ \int x^4 dx = \frac{1}{5}, \quad \int x^5 dx = \frac{1}{6} \]

Step 4:
Combine
\[ = \frac{1}{2} - 4\cdot\frac{1}{3} + 6\cdot\frac{1}{4} - 4\cdot\frac{1}{5} + \frac{1}{6} \] \[ = \frac{1}{2} - \frac{4}{3} + \frac{3}{2} - \frac{4}{5} + \frac{1}{6} \] \[ = \frac{1}{30} \] Final Conclusion:
\[ = \frac{1}{30} \]
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