The value of \( \cosec x + \cot x \) is
Step 1: Rewrite in Terms of Half-Angle Identity Using the identity: \[ \cosec x + \cot x = \frac{1 + \cos x}{\sin x} \] Using the half-angle identity: \[ \cos x = 2 \cos^2 \frac{x}{2} - 1, \quad \sin x = 2 \sin \frac{x}{2} \cos \frac{x}{2} \] \[ \cosec x + \cot x = \frac{1 + (2\cos^2 \frac{x}{2} - 1)}{2 \sin \frac{x}{2} \cos \frac{x}{2}} \] \[ = \frac{2\cos^2 \frac{x}{2}}{2 \sin \frac{x}{2} \cos \frac{x}{2}} \] \[ = \frac{\cos \frac{x}{2}}{\sin \frac{x}{2}} = \cot \frac{x}{2} \]
Final Answer: \[ \boxed{\cot \frac{x}{2}} \]
In a triangle ABC,if \(cos^{2}A-sin^{2}B+cos^{2}C=0\) ,then the value of \(cosAcosBcosC\) is
Kepler's second law (law of areas) of planetary motion leads to law of conservation of