Step 1: Formula
In an LCR series circuit, $E = \sqrt{V_R^2 + (V_L - V_C)^2}$.
Step 2: Identification
From the image (4P), let $V_R = 40 \text{ V}$, $V_L = 40 \text{ V}$, and $V_C = 10 \text{ V}$.
Step 3: Calculation
$E = \sqrt{40^2 + (40 - 10)^2} = \sqrt{40^2 + 30^2}$.
$E = \sqrt{1600 + 900} = \sqrt{2500} = 50 \text{ V}$.
Final Answer: (C)