Question:

The unit step response of a first-order system reaches 63.2% of its final value at time:

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Useful benchmarks for a first-order step response to remember for exams:
At $t = \tau$: reaches $63.2\%$ of final value.
At $t = 2\tau$: reaches $86.5\%$ of final value.
At $t = 3\tau$: reaches $95.0\%$ of final value.
At $t = 4\tau$: reaches $98.2\%$ of final value (practically at steady state).
Updated On: Jul 3, 2026
  • \(2\tau\)
  • \(\tau\) (one time constant)
  • \(0.5\tau\)
  • \(3\tau\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
This question asks for the relationship between the time constant ($\tau$) of a first-order system and the time it takes for its step response to reach $63.2\%$ of its ultimate steady-state value.

Step 2: Key Formula or Approach:
The transfer function of a first-order system with gain $K_p$ and time constant $\tau$ is: \[ G(s) = \frac{Y(s)}{X(s)} = \frac{K_p}{\tau s + 1} \] For a unit step input, $X(s) = 1/s$. The response in the Laplace domain is: \[ Y(s) = \frac{K_p}{s(\tau s + 1)} \] Taking the inverse Laplace transform gives the time-domain response: \[ y(t) = K_p \left(1 - e^{-t/\tau}\right) \]

Step 3: Detailed Explanation:
The final (steady-state) value of the response as $t \to \infty$ is: \[ y(\infty) = \lim_{t \to \infty} K_p \left(1 - e^{-t/\tau}\right) = K_p \] Let us evaluate the response at time $t = \tau$ (one time constant): \[ y(\tau) = K_p \left(1 - e^{-\tau/\tau}\right) = K_p \left(1 - e^{-1}\right) \] The value of the mathematical constant $e$ is approximately $2.71828$.
Calculating $e^{-1}$: \[ e^{-1} \approx \frac{1}{2.71828} \approx 0.3678 \] Substituting this back into the equation: \[ y(\tau) = K_p (1 - 0.3678) = 0.6322 K_p \] Thus, at $t = \tau$, the response reaches exactly $63.2\%$ of its ultimate value $K_p$.
This is a fundamental definition of the time constant $\tau$ for any first-order system, representing the speed of the system's response.

Step 4: Final Answer
Therefore, the system reaches $63.2\%$ of its final value at $t = \tau$ (one time constant), corresponding to option (B).
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