Question:
The type of radioactive decay that involves the emission of a positron is
The type of radioactive decay that involves the emission of a positron is
Show Hint
Remember:
\[
\beta^- \rightarrow \text{electron emission}
\]
\[
\beta^+ \rightarrow \text{positron emission}
\]
\[
\alpha \rightarrow {}^{4}_{2}\mathrm{He}
\]
\[
\gamma \rightarrow \text{high-energy photon}
\]
Updated On: Jul 29, 2026
- \(\alpha\)-decay
- \(\beta^+\)-decay
- \(\beta^-\)-decay
- \(\gamma\)-decay
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The Correct Option is B
Solution and Explanation
Concept:
A positron is the antiparticle of an electron. It has
\[
\text{charge}=+e,
\]
and is emitted during \(\beta^+\)-decay.
Step 1: Recall the process of \(\beta^+\)-decay. In \(\beta^+\)-decay, a proton inside the nucleus transforms into a neutron. \[ p \rightarrow n+e^+ + \nu_e, \] where \[ e^+ = \text{positron}, \] \[ \nu_e = \text{neutrino}. \]
Step 2: Examine the other decay modes. \[ \alpha\text{-decay} \] emits a helium nucleus \[ {}^{4}_{2}\mathrm{He}. \] \[ \beta^-\text{-decay} \] emits an electron. \[ n \rightarrow p+e^-+\bar{\nu}_e. \] \[ \gamma\text{-decay} \] emits electromagnetic radiation (gamma photons). None of these emit positrons.
Step 3: Identify the correct decay. Only \[ \boxed{\beta^+\text{-decay}} \] involves the emission of a positron. Therefore, \[ \boxed{\text{Answer = (B)}} \]
Step 1: Recall the process of \(\beta^+\)-decay. In \(\beta^+\)-decay, a proton inside the nucleus transforms into a neutron. \[ p \rightarrow n+e^+ + \nu_e, \] where \[ e^+ = \text{positron}, \] \[ \nu_e = \text{neutrino}. \]
Step 2: Examine the other decay modes. \[ \alpha\text{-decay} \] emits a helium nucleus \[ {}^{4}_{2}\mathrm{He}. \] \[ \beta^-\text{-decay} \] emits an electron. \[ n \rightarrow p+e^-+\bar{\nu}_e. \] \[ \gamma\text{-decay} \] emits electromagnetic radiation (gamma photons). None of these emit positrons.
Step 3: Identify the correct decay. Only \[ \boxed{\beta^+\text{-decay}} \] involves the emission of a positron. Therefore, \[ \boxed{\text{Answer = (B)}} \]
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