Question:
The type of hybridization of the carbon atoms from left to right in \(CH_3 - CH = CH - CN\) is
The type of hybridization of the carbon atoms from left to right in \(CH_3 - CH = CH - CN\) is
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Single bond → \(sp^3\), double bond → \(sp^2\), triple bond → \(sp\).
Updated On: Apr 24, 2026
- \(sp^3, sp, sp, sp^2\)
- \(sp^3, sp^2, sp, sp\)
- \(sp^3, sp^2, sp^2, sp\)
- \(sp^3, sp^2, sp^2, sp^2\)
- \(sp^3, sp^2, sp, sp^2\)
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The Correct Option is C
Solution and Explanation
Concept:
Hybridization depends on number of sigma bonds and geometry.
Step 1: Analyze each carbon.
• \(CH_3\) $\rightarrow$ 4 sigma bonds → \(sp^3\)
• \(CH=\) $\rightarrow$ double bond → \(sp^2\)
• \(=CH\) $\rightarrow$ double bond → \(sp^2\)
• \(CN\) $\rightarrow$ triple bond → \(sp\)
Step 2: Write order.
\[ sp^3, sp^2, sp^2, sp \]
Step 1: Analyze each carbon.
• \(CH_3\) $\rightarrow$ 4 sigma bonds → \(sp^3\)
• \(CH=\) $\rightarrow$ double bond → \(sp^2\)
• \(=CH\) $\rightarrow$ double bond → \(sp^2\)
• \(CN\) $\rightarrow$ triple bond → \(sp\)
Step 2: Write order.
\[ sp^3, sp^2, sp^2, sp \]
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