Concept:
The total translational kinetic energy of an ideal gas is
\[
K=\frac{3}{2}nRT,
\]
where
\[
n=\text{number of moles},
\quad
R=\text{universal gas constant},
\quad
T=\text{absolute temperature}.
\]
Step 1: Calculate the number of moles of \(CO_2\).
Molar mass of \(CO_2\):
\[
M=44\ \text{g mol}^{-1}.
\]
Given mass,
\[
m=22\ \text{g}.
\]
Hence,
\[
n=\frac{m}{M}
=\frac{22}{44}
=\frac12.
\]
Step 2: Convert temperature into Kelvin.
\[
T=27^\circ C+273.
\]
\[
T=300\ K.
\]
Step 3: Calculate the translational kinetic energy.
\[
K
=
\frac32 nRT.
\]
Substituting,
\[
K
=
\frac32
\left(\frac12\right)
(8.314)(300).
\]
\[
K
=
\frac34(2494.2).
\]
\[
K
=
1870.65\ \text{J}.
\]
\[
K
\approx
1870.6\ \text{J}.
\]
Therefore,
\[
\boxed{K=1870.6\ \text{J}}
\]
\[
\boxed{\text{Answer = (A)}}
\]