The EPR (Electron Paramagnetic Resonance) spectrum shows hyperfine splitting due to interactions of the unpaired electron with nearby nuclei that have a non-zero nuclear spin.
In the •CH2OH radical:
All H nuclei have spin \( I = \frac{1}{2} \).
For \( n \) equivalent nuclei with spin \( I \), the number of hyperfine lines is given by:
\[ 2nI + 1 \]
The two CH2 hydrogens contribute:
\[ 2 \cdot \left(\frac{1}{2}\right) + 1 = 2 + 1 = 3 \text{ lines} \]
The OH hydrogen couples independently (non-equivalent), so each of the 3 lines splits further into:
\[ 2 \cdot \left(\frac{1}{2}\right) + 1 = 2 \text{ lines} \]
Therefore, total hyperfine lines:
\[ 3 \times 2 = \boxed{6} \]
An aqueous solution of Co(ClO4)2·6H2O is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is:

[Given: Atomic number of Co = 27]
In the 1H-NMR spectrum of the following molecule, the signal of proton Ha appears as:

The Vaska’s complex trans-IrCl(CO)(PPh3)2 shows a band at 1967 cm−1 for the \( \nu_{\text{CO}} \) stretching vibration in its infrared spectrum. The complex(es) that will show an increase in the \( \nu_{\text{CO}} \) stretching vibration from 1967 cm−1 is/are:
The 1H NMR spectrum of the given iridium complex at room temperature gave a single signal at 2.6 ppm, and its 31P NMR spectrum gave a single signal at 23.0 ppm. When the spectra were recorded at lower temperatures, both these signals split into a complex pattern. The intra-molecular dynamic processes shown by this molecule are:

Compound K displayed a strong band at 1680 cm−1 in its IR spectrum. Its 1H-NMR spectral data are as follows:
δ (ppm):
7.30 (d, J = 7.2 Hz, 2H)
6.80 (d, J = 7.2 Hz, 2H)
3.80 (septet, J = 7.0 Hz, 1H)
2.20 (s, 3H)
1.90 (d, J = 7.0 Hz, 6H)
The correct structure of compound K is:
what is the final product
intensity ratio of final product