The 1H NMR spectrum of the given iridium complex at room temperature gave a single signal at 2.6 ppm, and its 31P NMR spectrum gave a single signal at 23.0 ppm. When the spectra were recorded at lower temperatures, both these signals split into a complex pattern. The intra-molecular dynamic processes shown by this molecule are:

The iridium complex depicted exhibits fluxional behavior, as observed from the NMR data. At room temperature:
At lower temperatures, these signals resolve into more complex multiplets, indicating slowed intramolecular processes.
This behavior suggests:
These dynamic motions average the chemical environments, causing single resonances in NMR at higher temperatures. On cooling, the slower motions lead to distinct environments and signal splitting.
Therefore, the dynamic processes involved are Berry pseudo-rotation and propeller-type rotation of the ethylene units along the Ir–alkene axis.
\[ \boxed{\text{Correct answer is (B)}} \]
An aqueous solution of Co(ClO4)2·6H2O is light pink in colour. Addition of conc. HCl results in an intense blue coloured solution due to the formation of a new species. The new species among the following is:

[Given: Atomic number of Co = 27]
In the 1H-NMR spectrum of the following molecule, the signal of proton Ha appears as:

The Vaska’s complex trans-IrCl(CO)(PPh3)2 shows a band at 1967 cm−1 for the \( \nu_{\text{CO}} \) stretching vibration in its infrared spectrum. The complex(es) that will show an increase in the \( \nu_{\text{CO}} \) stretching vibration from 1967 cm−1 is/are:
Compound K displayed a strong band at 1680 cm−1 in its IR spectrum. Its 1H-NMR spectral data are as follows:
δ (ppm):
7.30 (d, J = 7.2 Hz, 2H)
6.80 (d, J = 7.2 Hz, 2H)
3.80 (septet, J = 7.0 Hz, 1H)
2.20 (s, 3H)
1.90 (d, J = 7.0 Hz, 6H)
The correct structure of compound K is:
what is the final product
intensity ratio of final product