The topmost point of a vertical pole is A, bottom is D. Points B and C are between A and D. From a point E on the ground:
∠ of elevation to A = 60°,
∠ of elevation to B = 45°,
∠ of elevation to C = 30°.
Find the ratio \( AB : BC : CD \).
Let ED = \(x\), and AD = \(h\).
\(\tan 60^\circ = \frac{h}{x} \Rightarrow h = x\sqrt{3}\)
\(\tan 45^\circ = \frac{BD}{x} \Rightarrow BD = x\)
\(\tan 30^\circ = \frac{CD}{x} \Rightarrow CD = \frac{x}{\sqrt{3}}\)
Since AD = \(x\sqrt{3}\):
\(AB = AD - BD = x\sqrt{3} - x = x(\sqrt{3} - 1)\)
\(BC = BD - CD = x - \frac{x}{\sqrt{3}} = x\left(\frac{\sqrt{3} - 1}{\sqrt{3}}\right)\)
\(CD = \frac{x}{\sqrt{3}}\)
Ratio: \[ AB : BC : CD = (x(\sqrt{3} - 1)) : \Big(x\frac{\sqrt{3} - 1}{\sqrt{3}}\Big) : \frac{x}{\sqrt{3}} \] Cancelling \(x\) and multiplying by \(\sqrt{3}\): \[ (3 - \sqrt{3}) : (\sqrt{3} - 1) : 1 \]
\( AB : BC : CD = (3 - \sqrt{3}) : (\sqrt{3} - 1) : 1 \)