Step 1: Understanding the Concept
Vectors form a closed triangle only if they add to zero in some combination, for example \(\vec A\pm\vec B\pm\vec C=\vec 0\).
Step 2: Test the combinations
\(\vec A+\vec B=4\hat i-5\hat j+6\hat k\ne\pm\vec C\)
\(\vec A-\vec B=2\hat i+\hat j-4\hat k\ne\pm\vec C\)
\(\vec A\pm\vec C\) gives \(5\hat i-3\hat j+5\hat k\) or \(\hat i-\hat j-3\hat k\), neither equal to \(\pm\vec B\).
Step 3: Conclusion
No combination gives the zero vector, so the three vectors cannot form a triangle: option (C).
Final Answer:
The three vectors do not form any triangle.
\[ \boxed{\text{(C) }\text{no triangle}} \]