Step 1: List the number of students entering each year.
The question says 1996-97 had 1000 students and this number rises by 1000 every year, so the nine years give 1000, 2000, 3000, 4000, 5000, 6000, 7000, 8000, and 9000 students respectively, for 1996-97 through 2004-05.
Step 2: Use the primary total drop-out rate for each year from the table.
The primary total drop-out rates for these nine years are 40.2, 39.2, 41.5, 40.3, 40.7, 39.0, 34.8, 31.5, and 29.0 percent. Multiplying each year's student count by its rate gives that year's number of drop-outs.
Step 3: Work out the drop-out count year by year.
1996-97: \(1000 \times 0.402 = 402\).
1997-98: \(2000 \times 0.392 = 784\).
1998-99: \(3000 \times 0.415 = 1245\).
1999-2000: \(4000 \times 0.403 = 1612\).
2000-01: \(5000 \times 0.407 = 2035\).
2001-02: \(6000 \times 0.390 = 2340\).
2002-03: \(7000 \times 0.348 = 2436\).
2003-04: \(8000 \times 0.315 = 2520\).
2004-05: \(9000 \times 0.290 = 2610\).
Step 4: Add up all nine years.
\[
402+784+1245+1612+2035+2340+2436+2520+2610 = 15984
\]
This total, about 16,000, is closest to the option 16,000. The other options, 18,500, 24,500, and 19,500, are all noticeably higher than this total.
Final Answer:
The total number of drop-outs from primary classes, added up over 1996-97 to 2004-05, is approximately 16,000.
\[ \boxed{16{,}000} \]