Question

The sum of the total number of stereoisomers (including enantiomers) present in the following molecules is _____.

Answer 1

Correct Answer: 5 - 7

To determine the total number of stereoisomers for the given molecules, we follow these steps:

Molecule 1:
The first molecule contains two chiral centers (carbon atoms with four different groups attached). The formula to calculate the maximum number of stereoisomers is \(2^n\), where \(n\) is the number of chiral centers.

• For this molecule, \(n = 2\).
• Thus, number of stereoisomers = \(2^2 = 4\).

Molecule 2:
This molecule has one chiral center and is also a bicyclic compound, with the possibility of cis-trans isomerism. However, only the presence of one chiral center directly affects the stereoisomer count.

• For this molecule, \(n = 1\).
• Thus, number of stereoisomers = \(2^1 = 2\).

Total Stereoisomers:
The total number of stereoisomers, including enantiomers, is the sum of the stereoisomers of both molecules: \(4 + 2 = 6\).

The computed number of stereoisomers (6) fits within the expected range of 5 to 7.