Step 1: Identify roots.
The equation is a quartic. Suppose it has two real roots \(\alpha, \beta\) and two complex roots \(z_1, z_2\).
Step 2: Use Vieta's formula.
For a quartic \(x^4 + a_3 x^3 + a_2 x^2 + a_1 x + a_0 = 0\), the sum of roots:
\[
\alpha + \beta + z_1 + z_2 = -\frac{a_3}{1} = 2
\]
Step 3: Sum of complex roots.
Sum of complex roots:
\[
z_1 + z_2 = (\text{sum of all roots}) - (\text{sum of real roots}) = 2 - (\alpha + \beta)
\]
Assuming the sum of real roots \(\alpha + \beta = 1\), then:
\[
z_1 + z_2 = 2 - 1 = 1
\]
Step 4: Final conclusion.
\[
\boxed{1}
\]