Question

The steady state current in the circuit shown below is :

• A. 0.67 A
• B. 1.5 A
• C. 2 A
• D. 1 A

Answer 1

The Correct Option is C

To find the steady state current in the given circuit, we need to analyze the circuit carefully. In steady state DC analysis, capacitors act as open circuits. Let's go through the steps: 

1. In steady state, the capacitor (5 μF) behaves as an open circuit, effectively removing the lower branch with the 5 Ω and 3 Ω resistors from the circuit.
2. Thus, the circuit is simplified to a series circuit with only the voltage source and the 2 Ω resistor.
3. The voltage across the 2 Ω resistor is the same as the battery voltage because it is the only remaining component in the circuit path.
4. Using Ohm's Law \(I = \frac{V}{R}\), we can calculate the current:
   \(I = \frac{10 \, \text{V}}{2 \, \Omega} = 5 \, \text{A}\)

Therefore, the steady state current in the circuit is 5 A, not 2 A as given in the options. Please verify there is no additional factor or error in the original problem statement.