Question

The standard reduction potential of Zn\(^{2+}\)/Zn is \(-0.76\) V and Cu\(^{2+}\)/Cu is \(+0.34\) V. The EMF of the cell Zn | Zn\(^{2+}\) || Cu\(^{2+}\) | Cu is:

• A. 1.10 V
• B. -1.10 V
• C. 0.42 V
• D. -0.42 V

Hint:

Cell EMF = cathode potential − anode potential.

Answer 1

The Correct Option is A

\[ E^\circ_{\text{cell}}=E^\circ_{\text{cathode}}-E^\circ_{\text{anode}} =0.34-(-0.76)=1.10\ \text{V} \]