Question

The standard reduction potential for \( \text{Cu}^{2+} / \text{Cu} \) is +0.34 V. Calculate the reduction potential at pH = 14 for the above couple. \[ K_{sp} (\text{Cu(OH)}_2) = 1 \times 10^{-19} \]

• A. -0.22 V
• B. +0.22 V
• C. -0.44 V
• D. +0.44 V

Hint:

Use the Nernst equation to calculate reduction potentials at non-standard conditions, such as different pH or concentrations.

Answer 1

The Correct Option is B

Step 1: Use the Nernst equation.
The Nernst equation is: \[ E = E^0 - \frac{0.0591}{n} \log Q \] Substitute the given values to calculate the potential at pH 14.
Step 2: Conclusion.
After calculations, the reduction potential at pH 14 is found to be +0.22 V.
Final Answer: \[ \boxed{+0.22 \, \text{V}} \]