Step 1: Understanding the Question:
We are given standard reduction potentials (E°) for three metals. We must determine which statement about their spontaneous redox behavior is correct.
Step 2: Key Formula or Approach:
The standard reduction potential (E°) measures the tendency for a species to be reduced.
- A more negative E° indicates a stronger reducing agent (the metal is more easily oxidized).
- A more positive E° indicates a stronger oxidizing agent (the ion is more easily reduced).
A metal can spontaneously reduce the ions of another metal that has a more positive E°.
Step 3: Detailed Explanation:
Let's list the potentials in increasing order to create an electrochemical series:
E°(Zn\(^{2+}\)/Zn) = -0.76 V
E°(Cu\(^{2+}\)/Cu) = +0.34 V
E°(Ag\(^+\)/Ag) = +0.80 V
This order establishes the relative strengths:
- Strength as
reducing agents (metals): Zn $\gt $ Cu $\gt $ Ag.
- Strength as
oxidizing agents (ions): Ag\(^+\) $\gt $ Cu\(^{2+}\) $\gt $ Zn\(^{2+}\).
Now, let's evaluate each statement:
-
(A) Ag can oxidize Zn and Cu: Incorrect. The metal Ag is a reducing agent. Its ion, Ag\(^+\), is an oxidizing agent.
-
(B) Ag can reduce Zn\(^{2+}\) and Cu\(^{2+}\): Incorrect. Ag is the weakest reducing agent and cannot reduce ions of metals with lower (more negative) E° values.
-
(C) Zn can reduce Ag\(^+\) and Cu\(^{2+}\): Correct. Zn is the strongest reducing agent. Its E° is the most negative, so it can spontaneously reduce the ions of both Cu and Ag, which have more positive E° values.
-
(D) Cu can oxidize Zn and Ag: Incorrect. The metal Cu is a reducing agent. Its ion, Cu\(^{2+}\), can oxidize Zn but not Ag.
Step 4: Final Answer:
The correct statement is "Zn can reduce Ag\(^+\) and Cu\(^{2+}\)".