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the sides of a rectangle are given by x pm a and y
Question:
The sides of a rectangle are given by $x = \pm \, a$ and $y = \pm \, b$. The equation of the circle passing through the vertices of the rectangle is
MHT CET - 2018
MHT CET
Updated On:
May 7, 2024
$x^2 + y^2 = a^2$
$x^2 + y^2 = a^2 + b^2 $
$x^2 + y^2 = a^2 - b^2 $
$\left(x -a\right)^{2}+ \left(y-b\right)^{2} = a^{2} + b^{2} $
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The Correct Option is
B
Solution and Explanation
Given sides of rectangle are $x=\pm a$ and $ y=\pm b $ $\therefore$ Centre of circle $=(0,0)$ and radius of circle $=\sqrt{a^{2}+b^{2}}$
$\therefore$ Equation of circle $x^2 + y^2 = (a^2 + b^2)$
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