Question:

The roots of the equation \( x^4 - 5x^2 + 4 = 0 \) are

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When solving quadratic equations in terms of \( x^2 \), make sure to consider both positive and negative square roots.
Updated On: Apr 18, 2026
  • -2, 1, -2, -1
  • 2, -1, -2, 1
  • -2, -1, -1, -2
  • 2, 1, 1, 2
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The Correct Option is B

Solution and Explanation

Step 1: Rewriting the equation.
The given equation is \( x^4 - 5x^2 + 4 = 0 \). Let \( y = x^2 \), so the equation becomes: \[ y^2 - 5y + 4 = 0 \]

Step 2:
Solving the quadratic equation.
Now, solve the quadratic equation \( y^2 - 5y + 4 = 0 \) by factoring: \[ (y - 1)(y - 4) = 0 \] So, \( y = 1 \) or \( y = 4 \).

Step 3:
Substituting \( y = x^2 \).
Since \( y = x^2 \), we substitute back to find the roots of \( x \):
- For \( y = 1 \), \( x^2 = 1 \), so \( x = 1 \) or \( x = -1 \).
- For \( y = 4 \), \( x^2 = 4 \), so \( x = 2 \) or \( x = -2 \).

Step 4:
Conclusion.
Therefore, the roots of the equation are \( 2, -1, -2, 1 \).

Final Answer: 2, -1, -2, 1.
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