Step 1: Reading the circuit:
The figure shows inputs A and B going into a gate with an OR shape and a small circle at its output (a NOR gate). Its output C then passes into a triangle with a circle (a NOT gate), giving output Y.
Step 2: Write the Boolean expressions:
\[ C = \overline{A + B}, \qquad Y = \overline{C} = \overline{\overline{A + B}} = A + B \]
Step 3: Truth table check:
A = 0, B = 0: C = 1, Y = 0. A = 0, B = 1: C = 0, Y = 1. A = 1, B = 0: C = 0, Y = 1. A = 1, B = 1: C = 0, Y = 1.
This is the OR truth table.
Step 4: Final Answer:
The combination is an OR gate with \(Y = A + B\), option (C).
Final Answer:
NOR followed by NOT gives an OR gate.
\[ \boxed{\text{(C) }\text{OR},\ A+B} \]