The resultant capacitance between A and B in the following figure is equal to

1 \(\mu F\)
3 \(\mu F\)
2 \(\mu F\)
1.5 \(\mu F\)
The correct answer is (a): 1 µF
The rearrangement of the circuit is shown below.
The capacitors shown in the rectangular dotted line are in series and the capacitors shown in the circular dotted line are in parallel.


Two charges \( +q \) and \( -q \) are placed at points \( A \) and \( B \) respectively which are at a distance \( 2L \) apart. \( C \) is the midpoint of \( AB \). The work done in moving a charge \( +Q \) along the semicircle CSD (\( W_1 \)) and along the line CBD (\( W_2 \)) are 
Find work done in bringing charge q = 3nC from infinity to point A as shown in the figure : 