Question:
The resolving power of a microscope can be increased by selecting an appropriate medium between the object and objective lens. For a fixed wavelength of light, resolving power increases with:
The resolving power of a microscope can be increased by selecting an appropriate medium between the object and objective lens. For a fixed wavelength of light, resolving power increases with:
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Resolving power increases when wavelength decreases; higher refractive index reduces effective wavelength.
Updated On: Jun 19, 2026
- A medium with high density
- A medium with high refractive index
- A medium with low refractive index
- A medium with high viscosity
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The Correct Option is B
Solution and Explanation
Step 1: Resolving power relation.
\[ \text{Resolving power} \propto \frac{1}{\lambda/n} \] where \(n\) is refractive index of medium.
Step 2: Effect of refractive index.
Effective wavelength in medium: \[ \lambda' = \frac{\lambda}{n} \]
Step 3: Relation to resolving power.
Higher refractive index reduces wavelength, improving resolution.
Step 4: Eliminate incorrect options.
Density and viscosity do not directly affect optical resolving power.
Step 5: Key conclusion.
Thus, higher refractive index increases resolving power.
Step 6: Final conclusion.
Hence correct answer is medium with high refractive index.
Final Answer: \[ \boxed{\text{A medium with high refractive index}} \]
\[ \text{Resolving power} \propto \frac{1}{\lambda/n} \] where \(n\) is refractive index of medium.
Step 2: Effect of refractive index.
Effective wavelength in medium: \[ \lambda' = \frac{\lambda}{n} \]
Step 3: Relation to resolving power.
Higher refractive index reduces wavelength, improving resolution.
Step 4: Eliminate incorrect options.
Density and viscosity do not directly affect optical resolving power.
Step 5: Key conclusion.
Thus, higher refractive index increases resolving power.
Step 6: Final conclusion.
Hence correct answer is medium with high refractive index.
Final Answer: \[ \boxed{\text{A medium with high refractive index}} \]
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