Step 1: Understand the concept
For a meter bridge, balance gives \(\dfrac{X}{3X} = \dfrac{l}{100 - l}\), with \(l\) measured from the end where \(X\) is connected.
Step 2: First balance point
\(\dfrac{1}{3} = \dfrac{l}{100 - l}\) gives \(100 - l = 3l\), so \(l = 25\) cm.
Step 3: After interchange
The ratio becomes \(\dfrac{3X}{X} = 3 = \dfrac{l'}{100 - l'}\), so \(l' = 300 - 3l'\) and \(l' = 75\) cm.
Step 4: Shift
The shift is \(75 - 25 = 50\) cm, option (C).
Final Answer:
The balance point shifts by 50 cm. This is option (C).
\[ \boxed{\text{(C) }50\ \text{cm}} \]