Question

The resistance of a 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0.88 cm\(^{-1}\). The value of equivalent conductance of solution is:

• A. 400 mho cm² g\(^{-1}\)
• B. 295 mho cm² g\(^{-1}\)
• C. 419 mho cm² g\(^{-1}\)
• D. 425 mho cm² g\(^{-1}\)

Hint:

The equivalent conductance is the product of conductivity and the volume of the solution divided by the mass of the electrolyte.

Answer 1

The Correct Option is C

Step 1: The equivalent conductance is calculated using the formula: \[ \Lambda = \dfrac{K \cdot 1000}{c}, \] where \( K \) is the conductivity, and \( c \) is the concentration in g/L.
Step 2: Given the resistance and cell constant, calculate the conductivity and substitute to find the equivalent conductance.

Final Answer: \[ \boxed{419 \, \text{mho} \, \text{cm}^2 \, \text{g}^{-1}} \]