Question

The relation between total magnetic field \((B)\), magnetic intensity \((H)\), permeability of free space \((\mu _{0})\) and susceptibility \((\chi )\) is

• A. \(\frac{B}{H}=\mu _{0}(1+\chi )\)
• B. \(BH=\mu _{0}(1+\chi )\)
• C. \(\frac{H}{B}=\mu _{0}(1-\chi )\)
• D. \(\frac{H}{B}=\mu _{0}(1+\chi )\)

Hint:

Total field is mu0 times H plus magnetisation, and magnetisation equals chi times H.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept
In a magnetic material, \(B=\mu_{0}(H+M)\).

Step 2: Use susceptibility
The magnetisation is \(M=\chi H\).

Step 3: Calculation
\(B=\mu_{0}(H+\chi H)=\mu_{0}(1+\chi)H\)
So \(\frac{B}{H}=\mu_{0}(1+\chi)\).

Step 4: Compare the options
This is option (A).

Final Answer:
B over H equals mu0 times one plus chi. \[ \boxed{\text{(A) }\dfrac{B}{H}=\mu_{0}(1+\chi)} \]