The reaction that does NOT define calcination is :
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- \(2\mathrm{Cu_2S} + 3\mathrm{O_2} \xrightarrow{\Delta} 2\mathrm{Cu_2O} + 2\mathrm{SO_2}\)
- \(\mathrm{CaCO_3\cdot MgCO_3} \xrightarrow{\Delta} \mathrm{CaO} + \mathrm{MgO} + 2\mathrm{CO_2}\)
- \(\mathrm{ZnCO_3} \xrightarrow{\Delta} \mathrm{ZnO} + \mathrm{CO_2}\)
- \(\mathrm{Fe_2O_3\cdot XH_2O} \xrightarrow{\Delta} \mathrm{Fe_2O_3} + \mathrm{XH_2O}\)
The Correct Option is A
Solution and Explanation
(2) Dolomite loses CO2: calcination. (3) ZnCO3 loses CO2: calcination. (4) Hydrated iron oxide loses water: calcination.
(1) Cu2S reacts with O2 to give Cu2O and SO2. This is oxidation of a sulphide ore in excess air, i.e. roasting, not calcination.
Answer: (1) 2Cu2S + 3O2 \(\rightarrow\) 2Cu2O + 2SO2 (roasting)
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