To solve this question, we need to understand the chemical reaction that occurs when Lead Sulphide (PbS) reacts with dilute nitric acid (HNO3).
The chemical reaction between lead sulphide and dilute nitric acid can be represented as follows:
\(PbS + 4HNO_3 \rightarrow Pb(NO_3)_2 + 2H_2O + 2NO_2 + S\)
Breaking down the reaction, we can observe the formation of the following products:
From the given options, we can analyze and conclude:
Based on the analysis, the correct answer is:
Nitrous oxide (N2O) is not formed in this reaction.
The reaction between Lead Sulphide (PbS) and dilute nitric acid (\(HNO_3\)) proceeds as follows:
\(PbS + 2HNO_3 \rightarrow Pb(NO_3)_2 + NO + S + H_2O\)
Key Points:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
2[Au(CN)2]– + Zn \(\to\) [Zn(CN)4]2– + 2Au\(\downarrow\) is which of these
(A) Redox reaction
(B) Displacement reaction
(C) Combination reaction
(D) Decomposition reaction
Among following compounds, the number of those present in copper matte is ___ .
\(CuCO _3\)
\(Cu _2 S\)
\(Cu _2 O\)
\(FeO\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)