Question:

The reaction of aryl halide with sodium metal in dry ether to give biphenyl is known as

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Aryl halides coupling with sodium form the Fittig reaction.
Updated On: Oct 1, 2026
  • Swartz reaction
  • Wurtz reaction
  • Fittig reaction
  • Wrutz-fittig reaction
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
Several named reactions couple halides using sodium metal in dry ether. Which name applies depends on the type of halide used.

Step 2: Key Formula or Approach:
Wurtz: two alkyl halides give an alkane. Wurtz-Fittig: an aryl halide plus an alkyl halide gives an alkyl benzene. Fittig: two aryl halides give a diaryl compound.

Step 3: Detailed Explanation:
Here the halide is an aryl halide, e.g. \(\text{C}_6\text{H}_5\text{Br}\), and it reacts alone.
\[ 2\text{C}_6\text{H}_5\text{Br} + 2\text{Na} \xrightarrow{\text{dry ether}} \text{C}_6\text{H}_5-\text{C}_6\text{H}_5 + 2\text{NaBr} \]
The product is biphenyl, so this is the Fittig reaction. Swarts reaction is halogen exchange using a metal fluoride, and it is unrelated to sodium coupling.

Final Answer:
The reaction is the Fittig reaction, option (C). \[ \boxed{\text{Fittig reaction}} \]
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