The reaction of aqueous $KMnO_4 \, with \, H_2O_2 \, in $ acidic medium is $3H_2SO_4+2KMnO_4+5H_2O_2 \rightarrow $
$\hspace5mm 5O_2+2MnSO_4+8H_2O+K_2SO_4 $
In the above reaction, $KMnO_4 \, oxidises \, H_2O_2 \, to \, O_2 $ and itself $[MnO_4^-]$ gets reduced to $Mn^{2+} $ ion as $MnSO_4. $ Hence, aqueous solution of $KMnO_4. $ with $H_2O_2 \, yields \, Mn^{2+} \, and \, O_2 $ in acidic conditions.