Question

The ratio of rate of diffusion of SO\(_2\) (M = 64) and oxygen (M = 32) is

• A. 1:1
• B. 2:1
• C. 1:2
• D. 1:1.414

Hint:

Lighter gases diffuse faster; rate \(\propto 1/\sqrt{M}\).

Answer 1

The Correct Option is D

Step 1: Understanding the Concept:
Graham's law: \(r \propto 1/\sqrt{M}\).
Step 2: Detailed Explanation:
\(\frac{r_{SO_2}}{r_{O_2}} = \sqrt{\frac{32}{64}} = \sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}} = 1:1.414\)
Step 3: Final Answer:
Ratio is 1:1.414.