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the ratio of frequencies of oscillations of two si
Question:
The ratio of frequencies of oscillations of two simple pendulums is \( 3:4 \). Their lengths are in the ratio
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Frequency of a simple pendulum varies inversely as square root of length.
MHT CET - 2020
MHT CET
Updated On:
Jan 26, 2026
\( 16 : 9 \)
\( 9 : 16 \)
\( \sqrt{3} : \sqrt{4} \)
\( \sqrt{4} : \sqrt{3} \)
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The Correct Option is
A
Solution and Explanation
Step 1: Write frequency formula for simple pendulum.
\[ f = \frac{1}{2\pi}\sqrt{\frac{g}{L}} \]
Step 2: Write ratio of frequencies.
\[ \frac{f_1}{f_2} = \sqrt{\frac{L_2}{L_1}} \]
Step 3: Substitute given ratio.
\[ \frac{3}{4} = \sqrt{\frac{L_2}{L_1}} \]
Step 4: Square both sides.
\[ \frac{9}{16} = \frac{L_2}{L_1} \Rightarrow \frac{L_1}{L_2} = \frac{16}{9} \]
Step 5: Conclusion.
The ratio of lengths is \( 16 : 9 \).
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