Question:

The ratio of electric field amplitudes and magnetic field amplitudes in an electromagnetic wave in vacuum is equal to:

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For electromagnetic waves: \[ \frac{E_0}{B_0}=c \] where: \[ c=\text{speed of light in vacuum} \]
Updated On: May 21, 2026
  • Speed of light
  • Planck's constant
  • Gravitational constant
  • Permittivity of vacuum
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The Correct Option is A

Solution and Explanation

For an electromagnetic wave in vacuum: \[ \frac{E_0}{B_0}=c \] where:
• \(E_0\) = amplitude of electric field
• \(B_0\) = amplitude of magnetic field
• \(c\) = speed of light in vacuum
Step 1: Recall the relation
Electromagnetic waves consist of:
• Oscillating electric field
• Oscillating magnetic field The ratio of their amplitudes is always: \[ c=3\times10^8\ \text{m s}^{-1} \]
Step 2: Identify the correct option
Thus: \[ \frac{E_0}{B_0} = \text{Speed of light} \] Option analysis:
• Option (A): Correct
• Option (B): Incorrect
• Option (C): Incorrect
• Option (D): Incorrect Therefore: \[ \boxed{\text{(A)}} \]
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