Question:
The ratio of angular momentum \(L\) of an electron to the magnetic dipole moment \(\vec{\text{m}}_{\text{orb}}\) is ( '\(m\)' is mass of electron, '\(e\)' is charge on electron)
The ratio of angular momentum \(L\) of an electron to the magnetic dipole moment \(\vec{\text{m}}_{\text{orb}}\) is ( '\(m\)' is mass of electron, '\(e\)' is charge on electron)
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Remember relation: \(m = \frac{e}{2m}L\)
Updated On: Apr 26, 2026
- \(\frac{\text{e}}{\text{m}}\)
- \(\frac{2m}{e}\)
- \(\frac{\text{e}}{2\text{ m}}\)
- \(\frac{\text{m}}{\text{e}}\)
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The Correct Option is B
Solution and Explanation
Concept:
Magnetic dipole moment: \[ m_{\text{orb}} = \frac{e}{2m} L \] Step 1: Rearrange. \[ \frac{L}{m_{\text{orb}}} = \frac{2m}{e} \]
Step 2: Conclusion. \[ \frac{L}{m_{\text{orb}}} = \frac{2m}{e} \]
Magnetic dipole moment: \[ m_{\text{orb}} = \frac{e}{2m} L \] Step 1: Rearrange. \[ \frac{L}{m_{\text{orb}}} = \frac{2m}{e} \]
Step 2: Conclusion. \[ \frac{L}{m_{\text{orb}}} = \frac{2m}{e} \]
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