Question:

The rate of reaction between two reactants A and B decreases by a factor of 4 if the concentration of reactant B is doubled. The order of reaction with respect to reactant B is:

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If increasing concentration decreases rate, the reaction order is negative.
Updated On: Mar 19, 2026
  • 2
  • -2
  • 1
  • -1
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The Correct Option is D

Solution and Explanation

Step 1: Let the rate law be: Rate ∝ [B]ⁿ Step 2: When concentration of B is doubled: fracNew rateOld rate = (2)ⁿ Step 3: Given that rate decreases by a factor of 4: (2)ⁿ = (1)/(4) = 2⁻2 ⟹ n = -1
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