Question:

The rate of change of volume of spherical balloon at any instant is directly proportional to its surface area. If initially its radius is 3 cm, after 2 minutes its radius becomes 9 cm, then radius of balloon after 4 minutes is

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If $dV/dt \propto S$ for a sphere, the radius increases at a constant rate ($dr/dt = \text{const}$).
Updated On: Apr 30, 2026
  • 12 cm
  • 14 cm
  • 15 cm
  • 18 cm
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The Correct Option is C

Solution and Explanation

Step 1: Formulate Equation
$dV/dt = kS \implies 4\pi r^2 (dr/dt) = k(4\pi r^2)$.
$dr/dt = k$.
Step 2: Integrate
$r = kt + C$.
At $t=0, r=3 \implies C = 3$.
At $t=2, r=9 \implies 9 = 2k + 3 \implies 2k = 6 \implies k = 3$.
Step 3: Calculate final radius
At $t=4$: $r = (3)(4) + 3$.
$r = 12 + 3 = 15$ cm.
Step 4: Conclusion
The radius is 15 cm.
Final Answer:(C)
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