Question:

The rate of a reaction doubles when the initial concentration of the reactant is made fourfold. If the initial concentration is made 400 fold, then the rate will become:

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If rate doubles for 4× concentration \(\Rightarrow\) order = \(1/2\).
Updated On: Apr 16, 2026
  • 400 times
  • 200 times
  • 40 times
  • 20 times
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The Correct Option is D

Solution and Explanation

Concept: \[ \text{Rate} \propto [A]^n \]

Step 1:
Find order \(n\).
\[ 2 = 4^n \Rightarrow 2 = (2^2)^n = 2^{2n} \Rightarrow 2n = 1 \Rightarrow n = \frac{1}{2} \]

Step 2:
New concentration.
\[ \text{Rate} \propto (400)^{1/2} = 20 \]
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