Question

The rate constant of a reaction is \(k = 3.28\times 10^{-4}\) s\(^{-1}\). Find the order of the reaction.

• A. Zero order
• B. First order
• C. Second order
• D. Third order

Hint:

A rate constant with units of s^-1 means first order.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
The unit of \(k\) for order \(n\) is \(\text{mol}^{1-n}\,\text{L}^{n-1}\,\text{s}^{-1}\).

Step 2: Apply:
Zero order: mol L\(^{-1}\) s\(^{-1}\). First order: s\(^{-1}\). Second order: L mol\(^{-1}\) s\(^{-1}\). Third order: L\(^2\) mol\(^{-2}\) s\(^{-1}\).
The given \(k = 3.28\times10^{-4}\) s\(^{-1}\) has only the unit of time, so the reaction is first order.

Final Answer:
The reaction is of first order, option (B). \[ \boxed{\text{First order}} \]